Difference between revisions of "Menghitung Arah Kiblat"
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An example: Bakersfield California ( Fd = +35°23´ = 35.3833° | An example: Bakersfield California ( Fd = +35°23´ = 35.3833° | ||
Ld = 119°1´ = 119.0166° ) | Ld = 119°1´ = 119.0166° ) | ||
| − | Q = tan-1 sin (119.0166 – (-39. | + | Q = tan-1 sin (119.0166 – (-39.826162))[ (cos 35.3833) x (tan 21.45) ] – [ (sin 35.3833) x (cos 119.0166 – (-39.826162)) ] |
= [ { .3622 } ÷ { .3203 – (-.5397) } ] | = [ { .3622 } ÷ { .3203 – (-.5397) } ] | ||
= +22.863 degrees | = +22.863 degrees | ||
Latest revision as of 09:56, 15 September 2015
Sumber: http://akhbar.mumineen.org/archive/sharia/qibladir/
Q = tan-1 sin (Ld – Lm)[ (cos Fd) x (tan Fm) ] – [ (sin Fd) x (cos Ld – Lm) ]
Where: Fd = Latitude of Desired Location
Ld = Longitude of Desired Location
Fm = Latitude of Mecca (+21.422474 north of Equator)
Lm = Longitude of Mecca (-39.826162 east of Prime Meridian)
An example: Bakersfield California ( Fd = +35°23´ = 35.3833°
Ld = 119°1´ = 119.0166° )
Q = tan-1 sin (119.0166 – (-39.826162))[ (cos 35.3833) x (tan 21.45) ] – [ (sin 35.3833) x (cos 119.0166 – (-39.826162)) ]
= [ { .3622 } ÷ { .3203 – (-.5397) } ]
= +22.863 degrees
= +22°51´46.8″ East from True North