Difference between revisions of "Menghitung Arah Kiblat"

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(New page: Sumber: http://akhbar.mumineen.org/archive/sharia/qibladir/ Q = tan-1 sin (Ld – Lm)[ (cos Fd) x (tan Fm) ] – [ (sin Fd) x (cos Ld – Lm) ] Where: Fd = Latitude of Desired Locat...)
 
 
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  Where: Fd = Latitude of Desired Location
 
  Where: Fd = Latitude of Desired Location
 
                 Ld = Longitude of Desired Location
 
                 Ld = Longitude of Desired Location
                 Fm = Latitude of Mecca (+21.45° north of Equator)
+
                 Fm = Latitude of Mecca (+21.422474 north of Equator)
                 Lm = Longitude of Mecca (-39.75° east of Prime Meridian)
+
                 Lm = Longitude of Mecca (-39.826162 east of Prime Meridian)
  
  
 
  An example: Bakersfield California ( Fd = +35°23´ = 35.3833°
 
  An example: Bakersfield California ( Fd = +35°23´ = 35.3833°
 
                                       Ld = 119°1´ = 119.0166° )
 
                                       Ld = 119°1´ = 119.0166° )
  Q = tan-1 sin (119.0166 – (-39.75))[ (cos 35.3833) x (tan 21.45) ] – [ (sin 35.3833) x (cos 119.0166 – (-39.75)) ]
+
  Q = tan-1 sin (119.0166 – (-39.826162))[ (cos 35.3833) x (tan 21.45) ] – [ (sin 35.3833) x (cos 119.0166 – (-39.826162)) ]
 
   = [ { .3622 } ÷ { .3203 – (-.5397) } ]
 
   = [ { .3622 } ÷ { .3203 – (-.5397) } ]
 
   = +22.863 degrees
 
   = +22.863 degrees

Latest revision as of 09:56, 15 September 2015

Sumber: http://akhbar.mumineen.org/archive/sharia/qibladir/


Q = tan-1 	sin (Ld – Lm)[ (cos Fd) x (tan Fm) ] – [ (sin Fd) x (cos Ld – Lm) ]
Where: 	Fd = Latitude of Desired Location
               Ld = Longitude of Desired Location
               Fm = Latitude of Mecca (+21.422474 north of Equator)
               Lm = Longitude of Mecca (-39.826162 east of Prime Meridian)


An example: Bakersfield California ( Fd = +35°23´ = 35.3833°
                                     Ld = 119°1´ = 119.0166° )
Q = tan-1 	sin (119.0166 – (-39.826162))[ (cos 35.3833) x (tan 21.45) ] – [ (sin 35.3833) x (cos 119.0166 – (-39.826162)) ]
  = 	[ { .3622 } ÷ { .3203 – (-.5397) } ]
  = 	+22.863 degrees
  = 	+22°51´46.8″ East from True North


Referensi